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Tardigrade
Question
Mathematics
The combined equation of a pair of tangents to a circle drawn from the origin O be x y-y2=(2+√3)(x2-x y). The radius of the circle is 3 units and the centre is in first quadrant. Evaluate (2-√3)| OA | where A is one of the points of contact.
Q. The combined equation of a pair of tangents to a circle drawn from the origin
O
be
x
y
−
y
2
=
(
2
+
3
)
(
x
2
−
x
y
)
. The radius of the circle is
3
units and the centre is in first quadrant. Evaluate
(
2
−
3
)
∣
O
A
∣
where
A
is one of the points of contact.
80
184
Conic Sections
Report Error
Answer:
3
Solution:
x
y
−
y
2
=
(
2
+
3
)
(
x
2
−
x
y
)
⇔
y
(
x
−
y
)
=
(
2
+
3
)
(
x
)
(
x
−
y
)
⇔
(
x
−
y
)
[(
2
+
3
)
x
−
y
]
=
0
⇔
x
=
y
or
y
=
2
+
3
x
(Both equations represent lines with inclinations
4
5
∘
and
7
5
∘
)
∠
BO
A
=
3
0
∘
⇒
∠
CO
A
=
1
5
∘
∣
O
A
∣
=
∣
C
A
∣
cot
1
5
∘
=
2
−
3
3
⇒
(
2
−
3
)
∣
O
A
∣
=
3