The combination of gates shown in the figure below produces

Question

The combination of gates shown in the figure below produces <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-iorp2nnyij1k.png" /> (A) NOR gate (B) OR gate (C) AND gate (D) XOR gate

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-iorp2nnyozex.png" /> Here, the output of these gate Y = overline barA. bar B But according to Boolean algebra, overlineA. overlineB = overlineA+B ∴ Y = overline barA+ bar B = A+B or Y=A+B It means the whole circuit of gates behaves as OR gate

Q. The combination of gates shown in the figure below produces

NOR gate

OR gate

AND gate

XOR gate

Here, the output of these gate
$Y = \overline{\overset{ˉ}{A} . \overset{ˉ}{B}}$
But according to Boolean algebra,
$\overline{A} . \overline{B} = \overline{A + B}$
$∴ Y = \overline{\overset{ˉ}{A} + \overset{ˉ}{B}} = A + B$
or $Y = A + B$
It means the whole circuit of gates behaves as $OR$ gate

Q. The combination of gates shown in the figure below produces

NOR gate

OR gate

AND gate

XOR gate

Here, the output of these gate Y=Aˉ.Bˉ But according to Boolean algebra, A.B=A+B​ ∴Y=Aˉ+Bˉ​=A+B or Y=A+B It means the whole circuit of gates behaves as OR gate

Here, the output of these gate
$Y = \overline{\overset{ˉ}{A} . \overset{ˉ}{B}}$
But according to Boolean algebra,
$\overline{A} . \overline{B} = \overline{A + B}$
$∴ Y = \overline{\overset{ˉ}{A} + \overset{ˉ}{B}} = A + B$
or $Y = A + B$
It means the whole circuit of gates behaves as $OR$ gate