We know that, coefficient of xr in the expansion of (1+x)n is given by nCr. ∵ Coefficient of x5 in the expansion of (1+x)21+(1+x)22+…+(1+x)2n =21C5+22C5+…+30C5 =(21C6+21C5+22C5+…+30C5)−21C6 −(22C6+22Cb+…+30Cb)−21C6 [∵nCY+nCt−1=n+1CI] =23C6+23C5+…+30C6)−21C6
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...................................................... =(30C6+30C5)−21C6 =31C6−21C6