Q.
The coefficient of x2 in the expansion of (1+x+x2+x3)10 is
2793
181
J & K CETJ & K CET 2016Binomial Theorem
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Solution:
The given expansion is, (1+x+x2+x3)10=[1+x+x2(1+x)]10 =[(1+x)(1+x2)]10=(1+x)10(1+x2)10 =(1+10C1x+10C2x2+....+10C10x10) (1+10C1x2+10C2x4+....+10C10x20) ∴ Coefficient of x2=10C1+10C2=55