The coagulating power of an electrolyte for arsenious sulphide decreases in the order:

Question

The coagulating power of an electrolyte for arsenious sulphide decreases in the order: (A) Na +> Al 3+> Ba 2+ (B) P O43->S O42->C l- (C) Cl > SO 42-> PO 43- (D) A l3+>B a2+>N a+

Tardigrade Admin · Accepted Answer

According to Hardy Schuiz rule, the coagulating power of electrolyte increases with charge on ion.

∵ A_{s}_{2} S_{3}

is negatively charged colloid and so it will be coagulated by cations.

∴

Correct order of coagulating power for

A s_{2} S_{3}

is

A l^{3 +} > B a^{2 +} > N a^{+}

Q. The coagulating power of an electrolyte for arsenious sulphide decreases in the order:

$N a^{+} > A l^{3 +} > B a^{2 +}$

$P O_{4}^{3 -} > S O_{4}^{2 -} > C l^{-}$

$Cl > S O_{4}^{2 -} > P O_{4}^{3 -}$

$A l^{3 +} > B a^{2 +} > N a^{+}$

According to Hardy Schuiz rule, the coagulating power of electrolyte increases with charge on ion.
$∵ A_{s}_{2} S_{3}$ is negatively charged colloid and so it will be coagulated by cations.
$∴$ Correct order of coagulating power for $A s_{2} S_{3}$ is
$A l^{3 +} > B a^{2 +} > N a^{+}$

Q. The coagulating power of an electrolyte for arsenious sulphide decreases in the order:

Na+>Al3+>Ba2+

PO43−​>SO42−​>Cl−

Cl>SO42−​>PO43−​

Al3+>Ba2+>Na+

According to Hardy Schuiz rule, the coagulating power of electrolyte increases with charge on ion. ∵As​2​S3​ is negatively charged colloid and so it will be coagulated by cations. ∴ Correct order of coagulating power for As2​S3​ is Al3+>Ba2+>Na+

$N a^{+} > A l^{3 +} > B a^{2 +}$

$P O_{4}^{3 -} > S O_{4}^{2 -} > C l^{-}$

$Cl > S O_{4}^{2 -} > P O_{4}^{3 -}$

$A l^{3 +} > B a^{2 +} > N a^{+}$

According to Hardy Schuiz rule, the coagulating power of electrolyte increases with charge on ion.
$∵ A_{s}_{2} S_{3}$ is negatively charged colloid and so it will be coagulated by cations.
$∴$ Correct order of coagulating power for $A s_{2} S_{3}$ is
$A l^{3 +} > B a^{2 +} > N a^{+}$