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Tardigrade
Question
Physics
The circular divisions of shown screw gauge are 50. It moves 0.5 mm on main scale in one rotation. The diameter of the ball is
Q. The circular divisions of shown screw gauge are
50
. It moves
0.5
mm
on main scale in one rotation. The diameter of the ball is
2105
191
Manipal
Manipal 2014
Report Error
A
2.25 mm
B
2.20 mm
C
1.20 mm
D
1.25 mm
Solution:
Zero error
=
5
×
50
0.5
=
0.05
mm
Actual measurement
=
2
×
0.5
mm
+
25
×
50
0.5
−
0.05
mm
=
1
mm
+
0.25
mm
−
0.05
mm
=
1.20
mm