Q.
The chords passing through (2,1) intersect the hyperbola 16x2−9y2=1 at A and B. The locus of the point of intersection of tangents at A and B on the hyperbola is
Let, the point of intersection of the tangents at A & B is (h,k).
Then, the equation of AB is 16xh−9yk=1 { ∵T=0 is the chord of contact}
Now, 16xh−9yk=1 passes through (2,1)
Hence, 162h−9k=1 ⇒9h−8k=72 ⇒ the locus is 9x−8y=72