The chlorine end of the chlorine monoxide radical carries a charge of +0.167 e. The bond length is 154.6 pm. Calculate the dipole moment of the radical in Debye units.

Question

The chlorine end of the chlorine monoxide radical carries a charge of +0.167 e. The bond length is 154.6 pm. Calculate the dipole moment of the radical in Debye units. (A) 2.35 D (B) 1.24 D (C) 1.59 D (D) 2.05 D

Tardigrade Admin · Accepted Answer

vecμ= q ⋅ d q =1.167 e (1.602 × 10-19 c /1 e -) =2.675 × 10-20 C d =154.6 pm =154.6 × 10-12 m So vecμ=(2.675 × 10-20 C )(154.6 × 10-12) =4.136 × 10-30 Cm =(4.136 × 10-30/3.34 × 10-30)=1.24 D

Q. The chlorine end of the chlorine monoxide radical carries a charge of +0.167e. The bond length is 154.6pm. Calculate the dipole moment of the radical in Debye units.

2.35 D

1.24 D

1.59 D

2.05 D

μ​=q⋅d q=1.167e1e−1.602×10−19c​ =2.675×10−20C d=154.6pm=154.6×10−12m So μ​=(2.675×10−20C)(154.6×10−12) =4.136×10−30Cm =3.34×10−304.136×10−30​=1.24D

Q. The chlorine end of the chlorine monoxide radical carries a charge of $+ 0.167 e$ . The bond length is $154.6 p m$ . Calculate the dipole moment of the radical in Debye units.