Question

The cell, $Zn\left|Z{n}^{2+}\left(1M\right)\right|\left|C{u}^{2+}\left(1M\right)\right|Cu\left(E_{cell}^0=1.10V\right),$ was allowed to be completely discharged at $298K$. The relative concentration of $Z{n}^{2+}toC{u}^{2+}\left[\frac{\left[Z{n}^{2+}\right]}{\left[C{u}^{2+}\right]}\right]$ is

• A. antilog $(24.08)$
• B. $37.3$
• C. $10^{37.3}$
• D. $9.65\times 10^4$

Answer 1

Answer: (C)

$E_{cell}=E_{cell}^o-\frac{0.0591}{n}logQ$
Where $Q=\frac{\left[Z{n}^{2+}\right]}{\left[C{u}^{2+}\right]}$
For complete discharge $E_{cell}=0$
So $E_{cell}^o=\frac{0.591}{2}log\frac{\left[Z{n}^{2+}\right]}{\left[C{u}^{2+}\right]}$
$\Rightarrow \left|\frac{\left[Z{n}^{2+}\right]}{\left[C{u}^{2+}\right]}\right|=10^{37.3}$