Question

The cell reaction for the given cell is spontaneous if:

• A. $P_1>P_2$
• B. $P_1<P_2$
• C. $P_1=P_2$
• D. $P_2=1atm$

Answer 1

Answer: (B)

$E_{\text{cell }}=E_{O{P}_{Cl}}^0+E_{RPC{l}_{Cl}^0}^0+\frac{0.059}{2}\log$
$\frac{{\left[C{l}^{-}\right]}_{LHS}^2{P}_2}{{\left[C{l}^{-}\right]}_{RHS}^2{P}_1}=\frac{0.059}{2}\log \frac{P_2}{P_1}$
$E_{\text{cell }}$ is +ve when $P_2>P_1$