Question

The cell potential for the following cell
$Pt\left|H_2(g)\right|H^{+}(aq)\Vert C{u}^{2+}(0.01M)\mid Cu(s)$
is $0.576V$ at $298K$. The $pH$ of the solution is ___ (Nearest integer)

Answer 1

Answer: 5

$E_{\text{cell }}=E_{\text{cell }}^0-\frac{0.06}{2}\log \frac{{\left[H^{+}\right]}^2}{\left[C{u}^{2+}\right]}$
$0.576=0.34-\frac{0.06}{2}\log \left\{\frac{{\left[H^{+}\right]}^2}{(0.01)}\right\}$
$+3.93-\log \left(H^{+}\right)+\log 0.1$
$\Rightarrow pH=4.93\simeq 5$