The capacities and connection of five capacitors are shown in the figure below. The potential difference between the points A and B is 60 volts. Then the equivalent capacity between A and B and the charge on 5 μ F capacitance will be respectively

Question

The capacities and connection of five capacitors are shown in the figure below. The potential difference between the points A and B is 60 volts. Then the equivalent capacity between A and B and the charge on 5 μ F capacitance will be respectively (A) 44 μ F , 300 μ C (B) 16 μ F , 150 μ C (C) 15 μ F , 200 μ C (D) 4 μ F , 50 μ C

Tardigrade Admin · Accepted Answer

The given circuit can be redrawn as follows:

Equivalent capacitance of the circuit,

C_{A B} = 4 μ F

Charge given by the battery

Q = C_{e q} V = 4 \times 60 = 240 μ C

Charge in

5 μ F

capacitor

Q^{'} = \frac{5}{( 10 + 5 + 9 )} \times 240 = 50 μ C

Q. The capacities and connection of five capacitors are shown in the figure below. The potential difference between the points $A$ and $B$ is $60$ volts. Then the equivalent capacity between $A$ and $B$ and the charge on $5 μ F$ capacitance will be respectively

$44 μ F, 300 μ C$

$16 μ F, 150 μ C$

$15 μ F, 200 μ C$

$4 μ F, 50 μ C$

The given circuit can be redrawn as follows:

Equivalent capacitance of the circuit, $C_{A B} = 4 μ F$
Charge given by the battery
$Q = C_{e q} V = 4 \times 60 = 240 μ C$
Charge in $5 μ F$ capacitor
$Q^{'} = \frac{5}{( 10 + 5 + 9 )} \times 240 = 50 μ C$

Q. The capacities and connection of five capacitors are shown in the figure below. The potential difference between the points A and B is 60 volts. Then the equivalent capacity between A and B and the charge on 5μF capacitance will be respectively

44μF,300μC

16μF,150μC

15μF,200μC

4μF,50μC