The Brewster angle for the glass-air interface is 54.74°. If a ray of light going from air to glass strikes at an angle of incidence 45°, then the angle of refraction is (given, tan 54.74°=√2 )

Question

The Brewster angle for the glass-air interface is 54.74°. If a ray of light going from air to glass strikes at an angle of incidence 45°, then the angle of refraction is (given, tan 54.74°=√2 ) (A) 60° (B) 30° (C) 25° (D) 54.74°

Tardigrade Admin · Accepted Answer

Refractive index μ= tan θ=√2 Now according to snell's law √2=( sin (54.74)/ sin r) sin r=(0.816/√2) sin r=0.57 r=35° ≈ 30°

Q. The Brewster angle for the glass-air interface is $54.7 4^{\circ}$ . If a ray of light going from air to glass strikes at an angle of incidence $4 5^{\circ}$ , then the angle of refraction is (given, $tan 54.7 4^{\circ} = 2$ )

$6 0^{\circ}$

$3 0^{\circ}$

$2 5^{\circ}$

$54.7 4^{\circ}$

Refractive index $μ = tan θ = 2$
Now according to snell's law
$2 = \frac{s i n ( 54.74 )}{s i n r}$
$sin r = \frac{0.816}{2} sin r = 0.57$
$r = 3 5^{\circ} \approx 3 0^{\circ}$

Q. The Brewster angle for the glass-air interface is 54.74∘. If a ray of light going from air to glass strikes at an angle of incidence 45∘, then the angle of refraction is (given, tan54.74∘=2​ )

60∘

30∘

25∘

54.74∘