The breaking stress for a substance is 106 N / m 2. What length of the wire of this substance should be suspended vertically so that the wire breaks under its own weight? (Given: density of material of the wire =4 × 103 kg / m 3 and g=10 m s -2 )

Question

The breaking stress for a substance is 106 N / m 2. What length of the wire of this substance should be suspended vertically so that the wire breaks under its own weight? (Given: density of material of the wire =4 × 103 kg / m 3 and g=10 m s -2 ) (A) 10 m (B) 15 m (C) 25 m (D) 34 m

Tardigrade Admin · Accepted Answer

Breaking stress =( text Maximum weight / text Area of cross section ) 106=( text al ρ g/a)=l ρ g or l=(106/ρ g)=(106/4 × 103 × 10) m =25 m

Q. The breaking stress for a substance is $1 0^{6} N / m^{2}$ . What length of the wire of this substance should be suspended vertically so that the wire breaks under its own weight? (Given: density of material of the wire $= 4 \times 1 0^{3} k g / m^{3}$ and $g = 10 m s^{- 2}$ )

10 m

15 m

25 m

34 m

Breaking stress $= \frac{Maximum weight}{Area of cross section}$
$1 0^{6} = \frac{al ρ g}{a} = lρ g$
or $l = \frac{1 0 ^{6}}{ρ g} = \frac{1 0 ^{6}}{4 \times 1 0 ^{3} \times 10} m = 25 m$

Q. The breaking stress for a substance is 106N/m2. What length of the wire of this substance should be suspended vertically so that the wire breaks under its own weight? (Given: density of material of the wire =4×103kg/m3 and g=10ms−2 )