Question

The bond order of CO molecule is

• A. 2
• B. 2.5
• C. 3
• D. 3.5

Answer 1

Answer: (C)

$CO(6+8=14)=\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,\pi 2p_x^2\approx \sigma 2p_z^2$ $B.O.=\frac{N_b-N_a}{2}=\frac{10-4}{2}=3$