Question

The bond order of $CO$ molecule is

• A. 2
• B. 2.5
• C. 3
• D. 3.5

Answer 1

Answer: (C)

$CO(6+8=14)\sigma (1s{)}^2,{\sigma }^{\ast }(1s{)}^2,\sigma (2s{)}^2,{\sigma }^{\ast }(2s{)}^2,\pi {\left(2p_x\right)}^2\approx \pi {\left(2p_y\right)}^2,\sigma {\left(2p_z\right)}^2$
$B\cdot O=\frac{N_b-N_a}{2}$
$=\frac{10-4}{2}=3$