Question

The bond order in $O_2^{2-}$ is

• A. 2
• B. 3
• C. 1.5
• D. 1

Answer 1

Answer: (D)

Total number of electrons in $O_2^{2-}=18$
The electronic configuration of $O_2^{2-}$
will be $\sigma l{s}^2{\sigma }^{\ast }l{s}^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2$
$\pi 2p_x^2\pi 2p_y^2{\pi }^{\ast }2p_x^2{\pi }^{\ast }2p_y^2$
Bond order of a diatomic molecule is
given by the formula, $BO=\frac{N_b-N_a}{2}$
Bond order of $O_2^{2-}$ will be$\frac{10-8}{2}=1$