The bond order in CO 32- ion between C - O is :

Question

The bond order in CO 32- ion between C - O is : (A) zero (B)  0.88  (C)  1.33  (D)  2

Tardigrade Admin · Accepted Answer

We know that carbonate ion has following resonating structures <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/197ae923ddd16d87e819ae2444035ff5-.png" /> Bond order =( text total number of bonds between atoms / text total number of resonating structures ) =(1+1+2/3)=(4/3) =1.33

Q. The bond order in $C O_{3}^{2 -}$ ion between $C - O$ is :

zero

$0.88$

$1.33$

$2$

We know that carbonate ion has following resonating structures

Bond order $= \frac{total number of bonds between atoms}{total number of resonating structures}$
$= \frac{1 + 1 + 2}{3} = \frac{4}{3}$
$= 1.33$

Q. The bond order in CO32−​ ion between C−O is :

zero

0.88

1.33

2

We know that carbonate ion has following resonating structures Bond order = total number of resonating structures total number of bonds between atoms ​ =31+1+2​=34​ =1.33

Q. The bond order in $C O_{3}^{2 -}$ ion between $C - O$ is :

$0.88$

$1.33$

$2$

We know that carbonate ion has following resonating structures

Bond order $= \frac{total number of bonds between atoms}{total number of resonating structures}$
$= \frac{1 + 1 + 2}{3} = \frac{4}{3}$
$= 1.33$