The bond order in CO22- ion between C - O is

Question

The bond order in CO22- ion between C - O is (A) Zero (B) 0.88 (C) 1.33 (D) 2

Tardigrade Admin · Accepted Answer

We know that carbonate ion has following resonating structures <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/3dfa8cb5d4e5c4627eb5feb898ee4c94-.png" /> Bond order = ( textTotal number of bonds between atoms/ textTotal number of resonating structure) = (1 + 1 + 2/3) = (4/3) = 1.33

Q. The bond order in $C O_{2}^{2 -}$ ion between $C - O$ is

Zero

$0.88$

$1.33$

$2$

We know that carbonate ion has following resonating structures

Bond order $= \frac{Total number of bonds between atoms}{Total number of resonating structure}$
$= \frac{1 + 1 + 2}{3} = \frac{4}{3} = 1.33$

Q. The bond order in CO22−​ ion between C−O is

Zero

0.88

1.33

2

We know that carbonate ion has following resonating structures Bond order =Total number of resonating structureTotal number of bonds between atoms​ =31+1+2​=34​=1.33

Q. The bond order in $C O_{2}^{2 -}$ ion between $C - O$ is

$0.88$

$1.33$

$2$

We know that carbonate ion has following resonating structures

Bond order $= \frac{Total number of bonds between atoms}{Total number of resonating structure}$
$= \frac{1 + 1 + 2}{3} = \frac{4}{3} = 1.33$