The boiling points of ethyl acetate and CH 3 OH, respectively, are 77° C and 65° C. Which of the following reactions can be shifted to the right by the distillation of the reaction mixture at about 66° C I. MeCOOEt + MeOH arrow II. MeCOOMe + EtOH arrow III. MeCOOMe + PhOH arrow IV. MeCOOPh + MeOH arrow

Question

The boiling points of ethyl acetate and CH 3 OH, respectively, are 77° C and 65° C. Which of the following reactions can be shifted to the right by the distillation of the reaction mixture at about 66° C I. MeCOOEt + MeOH arrow II. MeCOOMe + EtOH arrow III. MeCOOMe + PhOH arrow IV. MeCOOPh + MeOH arrow (A) (I), (II) (B) (II), (III) (C) (I), (III) (D) (II), (IV)

Tardigrade Admin · Accepted Answer

In (II), the products are ethyl acetate (boiling point

7 7^{\circ} C

) and

M e O H

(boiling point

6 5^{\circ} C

). Thus at

6 6^{\circ} C, M e O H

is removed due to distillation and equilibrium is shifted to R.H.S.
In (IV), phenyl acetate is more reactive than methyl acetate

Q. The boiling points of ethyl acetate and CH3​OH, respectively, are 77∘C and 65∘C. Which of the following reactions can be shifted to the right by the distillation of the reaction mixture at about 66∘C I. MeCOOEt+MeOH→ II. MeCOOMe+EtOH→ III. MeCOOMe+PhOH→ IV. MeCOOPh+MeOH→

(I), (II)

(II), (III)

(I), (III)

(II), (IV)

In (II), the products are ethyl acetate (boiling point 77∘C ) and MeOH (boiling point 65∘C ). Thus at 66∘C,MeOH is removed due to distillation and equilibrium is shifted to R.H.S. In (IV), phenyl acetate is more reactive than methyl acetate

In (II), the products are ethyl acetate (boiling point $7 7^{\circ} C$ ) and $M e O H$ (boiling point $6 5^{\circ} C$ ). Thus at $6 6^{\circ} C, M e O H$ is removed due to distillation and equilibrium is shifted to R.H.S.
In (IV), phenyl acetate is more reactive than methyl acetate