The benzene (V.P. = 268 mm) and ethylene chloride (V.P. = 236 mm) form ideal solution.The total pressure made by dissolving 2 moles ofbenzene and 3 moles of ethylene chloride will be

Question

The benzene (V.P. = 268 mm) and ethylene chloride (V.P. = 236 mm) form ideal solution.The total pressure made by dissolving 2 moles ofbenzene and 3 moles of ethylene chloride will be (A) 504 mm (B) 248.8 mm (C) 255.2 mm (D) none of these

Tardigrade Admin · Accepted Answer

PTotal = (2/5) × 268 + (3/5) × 236 = 107.2 + 141.6 =248.8 mm.

Q. The benzene (V.P. = 268 mm) and ethylene chloride (V.P. = 236 mm) form ideal solution.The total pressure made by dissolving 2 moles ofbenzene and 3 moles of ethylene chloride will be

504 mm

248.8 mm

255.2 mm

none of these

$P_{T o t a l} = \frac{2}{5} \times 268 + \frac{3}{5} \times 236$
= 107.2 + 141.6 =248.8 mm.

Q. The benzene (V.P. = 268 mm) and ethylene chloride (V.P. = 236 mm) form ideal solution.The total pressure made by dissolving 2 moles ofbenzene and 3 moles of ethylene chloride will be

504 mm

248.8 mm

255.2 mm

none of these

PTotal​=52​×268+53​×236 = 107.2 + 141.6 =248.8 mm.

$P_{T o t a l} = \frac{2}{5} \times 268 + \frac{3}{5} \times 236$
= 107.2 + 141.6 =248.8 mm.