Question

The average kinetic energy per molecule of the gas is

• A. $\frac{1}{2}kT$
• B. $\frac{3}{2}kT$
• C. $\frac{1}{2}RT$
• D. $\frac{3}{2}RT$

Answer 1

Answer: (B)

Average kinetic energy of one molecule of ideal gas
$E=\frac{3}{2}KT$