The average kinetic energy of an ideal gas per molecule in SI unit at 25° C will be

Question

The average kinetic energy of an ideal gas per molecule in SI unit at 25° C will be (A) 6.17 × 10-21 kJ (B) 6.17 × 10-21 J (C) 6.17 × 10-20 J (D) 7.16 × 10-20 J

Tardigrade Admin · Accepted Answer

The average kinetic energy of an ideal gas per molecule in SI units at

2 5^{\circ} C

will be

6.17 \times

1 0^{- 21} J

The average kinetic energy of an ideal gas per molecule is given by the expression Average kinetic energy

= \frac{3}{2} k T

Here,

k

is boltzmann constant and

T

is absolute temperature.

k = 1.36 \times 1 0^{- 23} J / K

T = 25 + 273 = 298 K

Average kinetic energy

= \frac{3}{2} \times 1.36 \times 1 0^{- 23} J / K \times 298 K

= 6.17 \times 1 0^{- 21} J

Q. The average kinetic energy of an ideal gas per molecule in SI unit at $2 5^{\circ} C$ will be

$6.17 \times 1 0^{- 21} k J$

$6.17 \times 1 0^{- 21} J$

$6.17 \times 1 0^{- 20} J$

$7.16 \times 1 0^{- 20} J$

Q. The average kinetic energy of an ideal gas per molecule in SI unit at 25∘C will be

6.17×10−21kJ

6.17×10−21J

6.17×10−20J

7.16×10−20J

Q. The average kinetic energy of an ideal gas per molecule in SI unit at $2 5^{\circ} C$ will be

$6.17 \times 1 0^{- 21} k J$

$6.17 \times 1 0^{- 21} J$

$6.17 \times 1 0^{- 20} J$

$7.16 \times 1 0^{- 20} J$