Question

The average kinetic energy of an ideal gas, per molecule at ${25}^{o}C$ will be

• A. $6.17\times {10}^{-21}J$
• B. $6.17\times {10}^{-20}J$
• C. $61.7\times {10}^{-21}J$
• D. $7.16\times {10}^{-20}J$

Answer 1

Answer: (A)

Here: Temperature $(T)={25}^{o}C=298K$ . Average kinetic energy permolecule $=\frac{3RT}{2n}=\frac{3\times 8.314\times 298}{2\times (6.02\times {10}^{23})}$ $=6.17\times {10}^{-21}J$ (where $R=8.314$ )