The arithmetic mean of the nine numbers in the given set 9,99,999, ldots ldots .999999999 is a 9 digit number N, all whose digits are distinct. The number N does not contain the digit

Question

The arithmetic mean of the nine numbers in the given set 9,99,999, ldots ldots .999999999 is a 9 digit number N, all whose digits are distinct. The number N does not contain the digit (A) 0 (B) 2 (C) 5 (D) 9

Tardigrade Admin · Accepted Answer

N =(1/9) 9+99+999+ ldots .+999999999 =1+11+111+ ldots ldots+111111111 =123456789 ⇒ text (A)

Q. The arithmetic mean of the nine numbers in the given set ${9, 99, 999, \dots\dots .999999999}$ is a 9 digit number $N$ , all whose digits are distinct. The number $N$ does not contain the digit

0

2

5

9

$N = \frac{1}{9} {9 + 99 + 999 + \dots . + 999999999} = 1 + 11 + 111 + \dots\dots + 111111111$
$= 123456789 \Rightarrow (A)$

Q. The arithmetic mean of the nine numbers in the given set {9,99,999,…….999999999} is a 9 digit number N, all whose digits are distinct. The number N does not contain the digit

0

2

5

9

N=91​{9+99+999+….+999999999}=1+11+111+……+111111111 =123456789⇒ (A)

Q. The arithmetic mean of the nine numbers in the given set ${9, 99, 999, \dots\dots .999999999}$ is a 9 digit number $N$ , all whose digits are distinct. The number $N$ does not contain the digit

$N = \frac{1}{9} {9 + 99 + 999 + \dots . + 999999999} = 1 + 11 + 111 + \dots\dots + 111111111$
$= 123456789 \Rightarrow (A)$