The area of the figure bounded by the parabola x=-2 y2, x=1-3 y2 is

Question

The area of the figure bounded by the parabola x=-2 y2, x=1-3 y2 is (A) (1/3) square unit (B) (4/3) square unit (C) 1 square unit (D) 2 square unit

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/0dfdfeb5f7290feae870f23ffbf58a1a-.png" /> A=∫ limits-11(1-3 y2)-(-2 y2) d y ⇒ A=2 ∫ limits01(1-y2) d y=(4/3)

Q. The area of the figure bounded by the parabola $x = - 2 y^{2}, x = 1 - 3 y^{2}$ is

$\frac{1}{3}$ square unit

$\frac{4}{3}$ square unit

$1$ square unit

$2$ square unit

$A = - 1 \int 1 (1 - 3 y^{2}) - (- 2 y^{2}) d y$
$\Rightarrow A = 2 0 \int 1 (1 - y^{2}) d y = \frac{4}{3}$

Q. The area of the figure bounded by the parabola x=−2y2,x=1−3y2 is

31​ square unit

34​ square unit

1 square unit

2 square unit