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Tardigrade
Question
Mathematics
The area defined by |y| ≤ e -| x |-(1/2) in cartesian co-ordinate system, is
Q. The area defined by
∣
y
∣
≤
e
−
∣
x
∣
−
2
1
in cartesian co-ordinate system, is
550
109
Application of Integrals
Report Error
A
(
4
−
2
ln
2
)
B
(
4
−
ln
2
)
C
(
2
−
ln
2
)
D
(
2
−
2
ln
2
)
Solution:
Combining (1) and (2) we have the required area given as
A
=
4
0
∫
l
n
2
(
e
−
x
−
2
1
)
d
x
=
4
(
2
1
−
2
1
ln
2
)
=
(
2
−
2
ln
2
)