The approximate depth of an ocean is 2700 m. The compressibility of water is 45.4 × 10-11 Pa -1 and density of water is 103 kg m -3. What fractional compression of water will be obtained at the bottom of the ocean?

Question

The approximate depth of an ocean is 2700 m. The compressibility of water is 45.4 × 10-11 Pa -1 and density of water is 103 kg m -3. What fractional compression of water will be obtained at the bottom of the ocean? (A) 0.8 × 10-2 (B) 1.0 × 10-2 (C) 1.2 × 10-2 (D) 1.4 × 10-2

Tardigrade Admin · Accepted Answer

Given, d=2700 m and ρ=103 kg m -3 Compressibility =45.4 × 10-11 Pa -1 The pressure at the bottom of ocean is given by p=ρ g d=103 × 10 × 2700=27 × 106 Pa So, fractional compression = compressibility × pressure =45.4 × 10-11 × 27 × 106 =1.2 × 10-2

Q. The approximate depth of an ocean is $2700 m$ . The compressibility of water is $45.4 \times 1 0^{- 11} P a^{- 1}$ and density of water is $1 0^{3} k g m^{- 3}$ . What fractional compression of water will be obtained at the bottom of the ocean?

$0.8 \times 1 0^{- 2}$

$1.0 \times 1 0^{- 2}$

$1.2 \times 1 0^{- 2}$

$1.4 \times 1 0^{- 2}$

Q. The approximate depth of an ocean is 2700m. The compressibility of water is 45.4×10−11Pa−1 and density of water is 103kgm−3. What fractional compression of water will be obtained at the bottom of the ocean?

0.8×10−2

1.0×10−2

1.2×10−2

1.4×10−2

Given, d=2700m and ρ=103kgm−3 Compressibility =45.4×10−11Pa−1 The pressure at the bottom of ocean is given by p=ρgd=103×10×2700=27×106Pa So, fractional compression = compressibility × pressure =45.4×10−11×27×106 =1.2×10−2

Q. The approximate depth of an ocean is $2700 m$ . The compressibility of water is $45.4 \times 1 0^{- 11} P a^{- 1}$ and density of water is $1 0^{3} k g m^{- 3}$ . What fractional compression of water will be obtained at the bottom of the ocean?

$0.8 \times 1 0^{- 2}$

$1.0 \times 1 0^{- 2}$

$1.2 \times 1 0^{- 2}$

$1.4 \times 1 0^{- 2}$