The angular velocity of second's hand of a watch will be

Question

The angular velocity of second's hand of a watch will be (A) (π / text60) text rad s- 1 (B) (π / text30) text rad s- 1 (C)  text60π text rad s- 1 (D)  text30π text rad s- 1

Tardigrade Admin · Accepted Answer

The angular velocity is given by ω =(Δ θ /Δ t) Where Δ θ is the angle made by the second's hand and Δ t is the time taken. In one minute, Δ θ =2π rad and Δ t=60s So, ω =(2 π rad/60 s)=(π /30)rads- 1

Q. The angular velocity of second's hand of a watch will be

$\frac{π}{60} rad s^{- 1}$

$\frac{π}{30} rad s^{- 1}$

$60 π rad s^{- 1}$

$30 π rad s^{- 1}$

The angular velocity is given by
$ω = \frac{Δ θ}{Δ t}$
Where $Δ θ$ is the angle made by the second's hand and $Δ t$ is the time taken.
In one minute, $Δ θ = 2 π r a d$ and $Δ t = 60 s$
So, $ω = \frac{2 π r a d}{60 s} = \frac{π}{30} r a d s^{- 1}$

Q. The angular velocity of second's hand of a watch will be

60π​ rad s−1

30π​ rad s−1

60π rad s−1

30π rad s−1

The angular velocity is given by ω=ΔtΔθ​ Where Δθ is the angle made by the second's hand and Δt is the time taken. In one minute, Δθ=2πrad and Δt=60s So, ω=60s2πrad​=30π​rads−1

$\frac{π}{60} rad s^{- 1}$

$\frac{π}{30} rad s^{- 1}$

$60 π rad s^{- 1}$

$30 π rad s^{- 1}$

The angular velocity is given by
$ω = \frac{Δ θ}{Δ t}$
Where $Δ θ$ is the angle made by the second's hand and $Δ t$ is the time taken.
In one minute, $Δ θ = 2 π r a d$ and $Δ t = 60 s$
So, $ω = \frac{2 π r a d}{60 s} = \frac{π}{30} r a d s^{- 1}$