The angular momentum of an electron in Bohr’s hydrogen atom whose energy is -3.4 eV, is

Question

The angular momentum of an electron in Bohr’s hydrogen atom whose energy is -3.4 eV, is (A) (5h/2 π )  (B) (h/2 π )  (C) (h/π )  (D) (2h/3π )

Tardigrade Admin · Accepted Answer

Energy of electron in nth orbit of hydrogen atom En = - (13.6/n2) eV ⇒ 3.4 = - (13.6/n2 ) ⇒ n2 = 4 or, n =2 Angular momentum of electron L = (nh/2π) = (2h/2π) = (h/π)

Q. The angular momentum of an electron in Bohr’s hydrogen atom whose energy is $- 3.4 e V$ , is

$\frac{5 h}{2 π}$

$\frac{h}{2 π}$

$\frac{h}{π}$

$\frac{2 h}{3 π}$

Energy of electron in nth orbit of hydrogen atom
$E_{n} = - \frac{13.6}{n ^{2}} e V$
$\Rightarrow 3.4 = - \frac{13.6}{n ^{2}}$
$\Rightarrow n^{2} = 4$
or, $n = 2$
Angular momentum of electron
$L = \frac{nh}{2 π} = \frac{2 h}{2 π} = \frac{h}{π}$

Q. The angular momentum of an electron in Bohr’s hydrogen atom whose energy is −3.4eV, is

2π5h​

2πh​

πh​

3π2h​