The amplitude and time period in SHM are 0.8 cm and 0.2 sec respectively. If the initial phase is π / 2 radian, then the equation representing SHM is -

Question

The amplitude and time period in SHM are 0.8 cm and 0.2 sec respectively. If the initial phase is π / 2 radian, then the equation representing SHM is - (A) y=0.8cos 10 π t (B) y=0.8sin π t (C) y=3× 0.8sin π t (D) y=0.8sin 1 0 π t

Tardigrade Admin · Accepted Answer

Use general equation of SHM y=asin (ω t + φ) =0.8sin (2 π t/0.2) + (π /2) =0.8sin (10 π t + (π /2)) =0.8cos 10π t

Q. The amplitude and time period in $S H M$ are $0.8 c m$ and $0.2 sec$ respectively. If the initial phase is $π /2$ radian, then the equation representing $S H M$ is -

$y = 0.8 cos 10 π t$

$y = 0.8 s inπ t$

$y = 3 \times 0.8 s inπ t$

$y = 0.8 s in 10 π t$

Use general equation of SHM

$y = a s in (ω t + ϕ)$
$= 0.8 s in {\frac{2 π t}{0.2} + \frac{π}{2}}$
$= 0.8 s in (10 π t + \frac{π}{2})$

$= 0.8 cos 10 π t$

Q. The amplitude and time period in SHM are 0.8cm and 0.2sec respectively. If the initial phase is π/2 radian, then the equation representing SHM is -

y=0.8cos10πt

y=0.8sinπt

y=3×0.8sinπt

y=0.8sin10πt