The amount of metallic Zn (atomic weight =65.4 ) required to react with aqueous sodium hydroxide to produce 1 g of H 2, is

Question

The amount of metallic Zn (atomic weight =65.4 ) required to react with aqueous sodium hydroxide to produce 1 g of H 2, is (A) 32.7 g (B) 98.1 g (C) 65.4 g (D) 16.3 g

Tardigrade Admin · Accepted Answer

Zn +2 NaOH (a q) longrightarrow Na 2 ZnO 4+ H 2 uparrow 1 mole of H 2 is produced by 1 mole of Zn, i.e. 2 g of H 2 is produced by 65.4 g of Zn ∴ 1 g of H 2 is produced by =(65.4/2) g =32.7 g

Q. The amount of metallic $Z n$ (atomic weight $= 65.4$ ) required to react with aqueous sodium hydroxide to produce $1 g$ of $H_{2}$ , is

32.7 g

98.1 g

65.4 g

16.3 g

$Z n + 2 N a O H (a q) ⟶ N a_{2} Z n O_{4} + H_{2} ↑$
$1$ mole of $H_{2}$ is produced by $1$ mole of $Z n$ ,
i.e. $2 g$ of $H_{2}$ is produced by $65.4 g$ of $Z n$
$∴ 1 g$ of $H_{2}$ is produced by
$= \frac{65.4}{2} g = 32.7 g$

Q. The amount of metallic Zn (atomic weight =65.4 ) required to react with aqueous sodium hydroxide to produce 1g of H2​, is