Question

The alternating current is given by
$i=\left\{\sqrt{42}\sin \left(\frac{2\pi }{T}t\right)+10\right\}A$
The r.m.s. value of this current is$.........A.$

Answer 1

Answer: 11

$f_{\text{rms }}^2=f_{1\text{rms }}^2+f_{2\text{rms }}^2$
$={\left(\frac{\sqrt{42}}{\sqrt{2}}\right)}^2+10^2$
$=121\Rightarrow f_{\text{ rms}}=11A$