The activation energy of a reaction can be determined from the slope of which of the following graphs ?

Question

The activation energy of a reaction can be determined from the slope of which of the following graphs ? (A) (lnK/T)vs.T (B) lnK∨ s⋅ (1/T) (C) (T/lnK) vs. (1/ T) (D) InKvs.T

Tardigrade Admin · Accepted Answer

Arrhenius equation K=A.e- Ea / RT⇒ lnK=lnA-(Ea/RT) so, activation energy of reaction can be de- termined from the slope of InKvs(1/ T)

Q. The activation energy of a reaction can be determined from the slope of which of the following graphs ?

$\frac{l n K}{T} v s . T$

$l n K \lor s \cdot \frac{1}{T}$

$\frac{T}{l n K}$ vs. $\frac{1}{T}$

$I n K v s . T$

Arrhenius equation
$K = A . e^{- E a / RT} \Rightarrow l n K = l n A - \frac{E a}{RT}$
so, activation energy of reaction can be de-
termined from the slope of $I n K v s \frac{1}{T}$

Q. The activation energy of a reaction can be determined from the slope of which of the following graphs ?

TlnK​vs.T

lnK∨s⋅T1​

lnKT​ vs. T1​

InKvs.T

Arrhenius equation K=A.e−Ea/RT⇒lnK=lnA−RTEa​ so, activation energy of reaction can be de- termined from the slope of InKvsT1​

$\frac{l n K}{T} v s . T$

$l n K \lor s \cdot \frac{1}{T}$

$\frac{T}{l n K}$ vs. $\frac{1}{T}$

$I n K v s . T$

Arrhenius equation
$K = A . e^{- E a / RT} \Rightarrow l n K = l n A - \frac{E a}{RT}$
so, activation energy of reaction can be de-
termined from the slope of $I n K v s \frac{1}{T}$