Q.
The acceleration to gravity at a height 1/20th of the radius of the earth above the earth surface is 9ms−2 . Its value at a point at an equal distance below the surface of the earth in ms−2 is about
2026
232
NTA AbhyasNTA Abhyas 2020Gravitation
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Solution:
At a height h , gh=g(1−R2h)
for h=20R we get 9=g(1−101)=109g
At a depth d , gd=g(1−Rd)
for d=20R gd=g(1−201)=2019g ⇒9gd=1819⇒gd=9.5ms−2