The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B. A man jumps to a height of 2 m on the surface of A. What is the height of jump by the same person on the planet B.

Question

The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B. A man jumps to a height of 2 m on the surface of A. What is the height of jump by the same person on the planet B. (A) 6 m (B) 2/3 m (C) 2/9 m (D) 18 m

Tardigrade Admin · Accepted Answer

The velocity of the mass while reaching the surface of both the planets will be same. i.e., √2 g prime h prime=√2 g h √2 × g × h prime=√2 × 9 g × 2 2 h prime=36 ⇒ h prime=18 m

Q. The acceleration due to gravity on the planet $A$ is $9$ times the acceleration due to gravity on planet $B . A$ man jumps to a height of $2 m$ on the surface of $A .$ What is the height of jump by the same person on the planet $B$ .

6 m

2/3 m

2/9 m

18 m

The velocity of the mass while reaching the surface of both the planets will be same.
i.e., $2 g^{'} h^{'} = 2 g h$
$2 \times g \times h^{'} = 2 \times 9 g \times 2 2 h^{'} = 36$
$\Rightarrow h^{'} = 18 m$

Q. The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B.A man jumps to a height of 2m on the surface of A. What is the height of jump by the same person on the planet B.

6 m

2/3 m

2/9 m

18 m

The velocity of the mass while reaching the surface of both the planets will be same. i.e., 2g′h′​=2gh​ 2×g×h′​=2×9g×2​2h′=36 ⇒h′=18m

Q. The acceleration due to gravity on the planet $A$ is $9$ times the acceleration due to gravity on planet $B . A$ man jumps to a height of $2 m$ on the surface of $A .$ What is the height of jump by the same person on the planet $B$ .

The velocity of the mass while reaching the surface of both the planets will be same.
i.e., $2 g^{'} h^{'} = 2 g h$
$2 \times g \times h^{'} = 2 \times 9 g \times 2 2 h^{'} = 36$
$\Rightarrow h^{'} = 18 m$