Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Suppose that f is differentiable for all x and that f prime( x ) ≤ 2 for all x. If f(1)=2 and f (4)=8 then f(2) has the value equal to
Q. Suppose that
f
is differentiable for all
x
and that
f
′
(
x
)
≤
2
for all
x
. If
f
(
1
)
=
2
and
f
(
4
)
=
8
then
f
(
2
)
has the value equal to
188
146
Application of Derivatives
Report Error
A
3
B
4
C
6
D
8
Solution:
Using LMVT for
f
in
[
1
,
2
]
∀
c
∈
(
1
,
2
)
2
−
1
f
(
2
)
−
f
(
1
)
=
f
′
(
c
)
≤
2
f
(
2
)
−
f
(
1
)
≤
2
⇒
f
(
2
)
≤
4
....(1)
again using LMVT in
[
2
,
4
]
∀
d
∈
(
2
,
4
)
4
−
2
f
(
4
)
−
f
(
2
)
=
f
′
(
d
)
≤
2
∴
f
(
4
)
−
f
(
2
)
≤
4
8
−
f
(
2
)
≤
4
4
≤
f
(
2
)
f
(
2
)
=
4
....(2)
from (1) and
(
2
)
f
(
2
)
=
4