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Question
Chemistry
Suppose 5 g of acetic acid are dissolved in one litre of ethanol. Assume no reaction in between them. Calculate molality of resulting solution if density of ethanol is 0.789(g/m L).
Q. Suppose
5
g
of acetic acid are dissolved in one litre of ethanol. Assume no reaction in between them. Calculate molality of resulting solution if density of ethanol is
0.789
m
L
g
.
520
167
NTA Abhyas
NTA Abhyas 2022
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A
0.1056
B
0.056
C
0.156
D
0.16
Solution:
Wt. of
C
H
3
COO
H
dissolved
=
5
g
Eq. of
C
H
3
COO
H
dissolved
=
60
5
Volume of ethanol
=
1
l
i
t
re
=
1000
m
L
∴
Weight of ethanol
=
(
1000
×
0.789
)
g
=
789
g
∴
M
o
l
a
l
i
t
y
o
f
so
l
u
t
i
o
n
=
wt
.
o
f
so
l
v
e
n
t
in
k
g
M
o
l
es
o
f
so
l
u
t
e
=
{
1000
60
×
789
5
}
=
0.1056