Sulphuryl chloride (SO2Cl2) reacts with white phosphorus (P4) to give

Question

Sulphuryl chloride (SO2Cl2) reacts with white phosphorus (P4) to give (A) PCl5, SO2 (B) OPCl3, SOCl2 (C) PCl5, SO2, S2Cl2 (D) OPCl3, SO2, S2Cl2

Tardigrade Admin · Accepted Answer

When sulphuryl chloride ( SO 2 Cl 2) reacts with white phosphorus ( P 4), it give phosphorus pentachloride ( PCl 5) and' sulphur dioxide ( SO 2). The reaction is as follows: P 4+10 SO 2 Cl 2 longrightarrow 4 PCl 5+10 SO 2

Q. Sulphuryl chloride $(S O_{2} C l_{2})$ reacts with white phosphorus $(P_{4})$ to give

$PC l_{5}, S O_{2}$

$OPC l_{3}, SOC l_{2}$

$PC l_{5}, S O_{2}, S_{2} C l_{2}$

$OPC l_{3}, S O_{2}, S_{2} C l_{2}$

When sulphuryl chloride $(S O_{2} C l_{2})$ reacts with white phosphorus $(P_{4})$ , it give phosphorus pentachloride $(PC l_{5})$ and' sulphur dioxide $(S O_{2})$ . The reaction is as follows:
$P_{4} + 10 S O_{2} C l_{2} ⟶ 4 PC l_{5} + 10 S O_{2}$

Q. Sulphuryl chloride (SO2​Cl2​) reacts with white phosphorus (P4​) to give

PCl5​,SO2​

OPCl3​,SOCl2​

PCl5​,SO2​,S2​Cl2​

OPCl3​,SO2​,S2​Cl2​