Sulphur-35 (34.96903 amu) emits a P-particle but no γ - ray. The product is chlorine-35 (34.96885 amu). The maximum energy of the β - particle emitted is :

Question

Sulphur-35 (34.96903 amu) emits a P-particle but no &gamma; - ray. The product is chlorine-35 (34.96885 amu). The maximum energy of the β - particle emitted is : (A) 1.6758 MeV (B) 16.758 MeV (C) 0.016758 MeV (D) 0.16758 MeV

Tardigrade Admin · Accepted Answer

Energy can be calculated by calculating the value of mass defect. Δ m=34.96903-34.96885 =0.00018 textamu text. Maximum energy dE=Δ m× 931.5 textMe textV =0.00018× 931.5 =0.16758 textMeV

Q. Sulphur-35 (34.96903 amu) emits a P-particle but no $γ -$ ray. The product is chlorine-35 (34.96885 amu). The maximum energy of the $β -$ particle emitted is :

1.6758 MeV

16.758 MeV

0.016758 MeV

0.16758 MeV

Energy can be calculated by calculating the value of mass defect. $Δ m = 34.96903 - 34.96885$ $= 0.00018 amu .$ Maximum energy $d E = Δ m \times 931.5 Me V$ $= 0.00018 \times 931.5$ $= 0.16758 MeV$

Q. Sulphur-35 (34.96903 amu) emits a P-particle but no γ− ray. The product is chlorine-35 (34.96885 amu). The maximum energy of the β− particle emitted is :