Sulphur-35 (34.96903 amu) emits a β particle but no γ-rays, the product is chlorine-35 (34.96885 amu). The maximum energy emitted by the β-particle is:

Question

Sulphur-35 (34.96903 amu) emits a β particle but no &gamma;-rays, the product is chlorine-35 (34.96885 amu). The maximum energy emitted by the β-particle is: (A) 0.016767 MeV (B) 1.6758 MeV (C) 0.016758 MeV (D) 16.758 MeV

Tardigrade Admin · Accepted Answer

The maximum energy emitted by β-particles is equal to binding energy. Binding/energy = mass defect × 931.5 MeV Given, mass of sulphur =34.96903 amu Mass of chlorine =34.96885 amu Mass defect = mass of sulphur - mass of chlorine =34.96903-34.96885=0.00018 amu ∴ Binding energy = mass defect × 931.5 MeV or =0.00018 × 931.5 MeV =0.16767 MeV

Q. Sulphur-35(34.96903amu)emits a β particle but no γ-rays, the product is chlorine-35(34.96885amu). The maximum energy emitted by the β-particle is:

0.016767 MeV

1.6758 MeV

0.016758 MeV

16.758 MeV

Q. Sulphur- $35 (34.96903 am u)$ emits a $β$ particle but no $γ$ -rays, the product is chlorine- $35 (34.96885 am u)$ . The maximum energy emitted by the $β$ -particle is: