Statement-I: Glycolysis is the first step of respiration in which glucose completely breaks into CO2 and H2O Statement-II: In this process, there is a net gain of twenty-four molecules of ATP.

Question

Statement-I: Glycolysis is the first step of respiration in which glucose completely breaks into CO2 and H2O Statement-II: In this process, there is a net gain of twenty-four molecules of ATP. (A) Only statement-I is correct. (B) Only statement-II is correct. (C) Both statement-I and statement-II are correct. (D) Both statement-I and statement-II are incorrect.

Tardigrade Admin · Accepted Answer

Glycolysis / EMP pathway:

Discovery: It is given by Embden, Meyerhoff, and Parnas in 1930. It is the first stage of the breakdown of glucose in the cell.
Definition: Glycolysis (Gr. glykys= sweet, sugar; lysis= breaking) is a stepped process by which one molecule of glucose (6C) breaks into two molecules of pyruvic acid (3C).
Site of occurrence: Glycolysis takes place in the cytosol and does not utilize oxygen. Thus, it is an anaerobic pathway. In fact, it occurs in both aerobic and anaerobic respiration.

Steps of glycolysis: Glycolysis consists of 10 steps divided into 2 phases preparatory phase and pay off phase. Each step is catalyzed by a specific enzyme. Most of the reactions are reversible. Preparatory phase: In this phase, 2 molecules of ATP are utilized. Pay-off phase: In this phase, energy is released in the form of ATP and NADH2 is formed. 8 ATP

Q. Statement-I: Glycolysis is the first step of respiration in which glucose completely breaks into CO2​ and H2​O Statement-II: In this process, there is a net gain of twenty-four molecules of ATP.

Only statement-I is correct.

Only statement-II is correct.

Both statement-I and statement-II are correct.

Both statement-I and statement-II are incorrect.

Q. Statement-I: Glycolysis is the first step of respiration in which glucose completely breaks into $C O_{2}$ and $H_{2} O$
Statement-II: In this process, there is a net gain of twenty-four molecules of $A TP .$