Statement-1: Two particles moving in the same direction do not lose all their energy in a completely inelastic collision. Statement-2: Principle of conservation of momentum holds true for all kinds of collisions.

Question

Statement-1: Two particles moving in the same direction do not lose all their energy in a completely inelastic collision. Statement-2: Principle of conservation of momentum holds true for all kinds of collisions. (A) Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation of Statement-1. (B) Statement-1 is true, Statement-2 is true; Statement-2 is not the correct explanation of Statement- 1 (C) Statement-1 is false, Statement-2 is true. (D) Statement-1 is true, Statement-2 is false.

Tardigrade Admin · Accepted Answer

If it is a completely inelastic collision then

m_{1} v_{1} + m_{2} v_{2} = m_{1} v + m_{2} v

v = \frac{m _{1} v _{1} + m _{2} v _{2}}{m _{1} + m _{2}}

K . E = \frac{p _{1}^{2}}{2 m _{1}} + \frac{p _{2}^{2}}{2 m _{2}}

as

p_{1}

and

p_{2}

both simultaneously cannot be zero
therefore total KE cannot be lost.

Q. Statement-1 : Two particles moving in the same direction do not lose all their energy in a completely inelastic collision. Statement-2 : Principle of conservation of momentum holds true for all kinds of collisions.

Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation of Statement-1.

Statement-1 is true, Statement-2 is true; Statement-2 is not the correct explanation of Statement- 1

Statement-1 is false, Statement-2 is true.

Statement-1 is true, Statement-2 is false.

If it is a completely inelastic collision then m1​v1​+m2​v2​=m1​v+m2​v v=m1​+m2​m1​v1​+m2​v2​​ K.E=2m1​p12​​+2m2​p22​​ as p1​​ and p2​​ both simultaneously cannot be zero therefore total KE cannot be lost.

Q. Statement-1 : Two particles moving in the same direction do not lose all their energy in a completely inelastic collision.
Statement-2 : Principle of conservation of momentum holds true for all kinds of collisions.