Statement-1: If n is an odd integer greater than 3 but not a multiple of 3 , then (x+1)n-xn-1 is divisible by x 3+ x 2+ x Statement-2: If n is an odd integer greater than 3 but not a multiple of 3 , we have 1+ω n +ω2 n =3

Question

Statement-1: If n is an odd integer greater than 3 but not a multiple of 3 , then (x+1)n-xn-1 is divisible by x 3+ x 2+ x Statement-2: If n is an odd integer greater than 3 but not a multiple of 3 , we have 1+ω n +ω2 n =3 (A) Both the Statements are true and Statement 2 is correct explanation of Statement 1 (B) Both the Statements are true and Statements 2 is not the correct explanation of Statement 1 (C) Statement- 1 is True, Statement- 2 is False (D) Statement-1 is False, Statement-2 is True

Tardigrade Admin · Accepted Answer

Correct answer is (c) Statement- 1 is True, Statement- 2 is False

Q. Statement-1: If n is an odd integer greater than 3 but not a multiple of 3 , then (x+1)n−xn−1 is divisible by x3+x2+x Statement-2 : If n is an odd integer greater than 3 but not a multiple of 3 , we have 1+ωn+ω2n=3

Both the Statements are true and Statement 2 is correct explanation of Statement 1

Both the Statements are true and Statements 2 is not the correct explanation of Statement 1

Statement- 1 is True, Statement- 2 is False

Statement-1 is False, Statement-2 is True

Correct answer is (c) Statement- 1 is True, Statement- 2 is False

Q. Statement-1: If $n$ is an odd integer greater than 3 but not a multiple of 3 , then $(x + 1)^{n} - x^{n} - 1$ is divisible by $x^{3} + x^{2} + x$
Statement-2 : If $n$ is an odd integer greater than 3 but not a multiple of 3 , we have $1 + ω^{n} + ω^{2 n} = 3$