Sodium metal crystallizes in a BCC lattice having a unit cell edge of 4.29 Å . The radius of sodium atom is approximately:

Question

Sodium metal crystallizes in a BCC lattice having a unit cell edge of 4.29 Å . The radius of sodium atom is approximately: (A) 0.93 Å (B) 1.86 Å (C) 3.22 Å (D) 5.72 Å

Tardigrade Admin · Accepted Answer

For BCC, 4r=√3a r=(√3/4)a=( text1.732/4)× text4.29 = text1.86 mathringA

Q. Sodium metal crystallizes in a BCC lattice having a unit cell edge of $4.29 Å$ . The radius of sodium atom is approximately:

$0.93 Å$

$1.86 Å$

$3.22 Å$

$5.72 Å$

For BCC,
$4 r = 3 a$
$r = \frac{3}{4} a = \frac{1.732}{4} \times 4.29$
$= 1.86 \overset{˚}{A}$

Q. Sodium metal crystallizes in a BCC lattice having a unit cell edge of 4.29Å . The radius of sodium atom is approximately:

0.93Å

1.86Å

3.22Å

5.72Å