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Tardigrade
Question
Chemistry
textSO2+ textNO+H2 textO arrow textX+ texta textdibasic textacid textX overset textNaNH text2 arrow textY+ textH text2 textO In the above sequence, X and Y are respectively
Q.
SO
2
+
NO+H
2
O
→
X+
a
dibasic
acid
X
→
NaNH
2
Y
+
H
2
O
In the above sequence, X and Y are respectively
46
182
NTA Abhyas
NTA Abhyas 2022
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A
NO
H
S
O
4
,
N
a
H
S
O
4
B
N
O
2
,
N
a
N
O
2
C
N
2
O
,
N
a
N
3
D
N
2
O
,
N
a
2
N
Solution:
Here X and Y are
N
2
O
,
N
a
N
3
S
O
2
+
2
NO
+
H
2
O
→
(
X
)
N
2
O
+
H
2
S
O
4
(
X
)
N
2
O
+
N
a
N
H
2
→
(
Y
)
N
a
N
3
+
H
2
O