Six particles each of mass 'm' are placed at the comers of a regular hexagon of edge length 'a'. If a point mass 'm0' is placed at the center of the hexagon, then the net gravitational force on the point mass 'm0' is

Question

Six particles each of mass 'm' are placed at the comers of a regular hexagon of edge length 'a'. If a point mass 'm0' is placed at the center of the hexagon, then the net gravitational force on the point mass 'm0' is (A) (6Gm2/a2) (B) (6Gmm2/a2) (C) zero (D) none of these

Tardigrade Admin · Accepted Answer

The force exerted by each particle placed on the vertices, over the particle at the centre are equal in magnitude and cancel each other vectorially. Thus the resultant force on it is equal to zero.

Q. Six particles each of mass 'm' are placed at the comers of a regular hexagon of edge length 'a'. If a point mass $^{'} m_{0}^{'}$ is placed at the center of the hexagon, then the net gravitational force on the point mass $^{'} m_{0}^{'}$ is

$\frac{6 G m ^{2}}{a ^{2}}$

$\frac{6 G m m _{2}}{a ^{2}}$

zero

none of these

The force exerted by each particle placed on the vertices, over the particle at the centre are equal in magnitude and cancel each other vectorially. Thus the resultant force on it is equal to zero.

Q. Six particles each of mass 'm' are placed at the comers of a regular hexagon of edge length 'a'. If a point mass ′m0′​ is placed at the center of the hexagon, then the net gravitational force on the point mass ′m0′​ is

a26Gm2​

a26Gmm2​​

zero

none of these

The force exerted by each particle placed on the vertices, over the particle at the centre are equal in magnitude and cancel each other vectorially. Thus the resultant force on it is equal to zero.

Q. Six particles each of mass 'm' are placed at the comers of a regular hexagon of edge length 'a'. If a point mass $^{'} m_{0}^{'}$ is placed at the center of the hexagon, then the net gravitational force on the point mass $^{'} m_{0}^{'}$ is

$\frac{6 G m ^{2}}{a ^{2}}$

$\frac{6 G m m _{2}}{a ^{2}}$