sin10° + sin 20° + sin 30° +...+ sin360° =

Question

sin10° + sin 20° + sin 30° +...+ sin360° = (A) 0 (B) 1 (C) √3 (D) 2

Tardigrade Admin · Accepted Answer

sin10° + sin20° + sin30°+...+ sin360° = sin10° + sin20° +........+ sin180° + sin190° +...+ sin 360° = ( sin10° + sin20° +...+ sin180° )+( sin190° + sin200° +.....+ sin360° ) = ( sin10° + sin20° + sin180° )+[ sin(180° + 10° )+ sin(180° + 20°)+....+ sin(180° +180°)] = ( sin 10° + sin 20° +...+ sin180° )+[- sin 10° - sin 20° - ..... - sin180° ] = 0

Q. $sin 1 0^{\circ} + sin 2 0^{\circ} + sin 3 0^{\circ} + ... + sin 36 0^{\circ} =$

$0$

$1$

$3$

$2$

Q. sin10∘+sin20∘+sin30∘+...+sin360∘=

0

1

3​

2

Q. $sin 1 0^{\circ} + sin 2 0^{\circ} + sin 3 0^{\circ} + ... + sin 36 0^{\circ} =$

$0$

$1$

$3$

$2$