Silver forms ccp lattice and X-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm The density of silver (Atomic mass = 107.9 u) is

Question

Silver forms ccp lattice and X-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm The density of silver (Atomic mass = 107.9 u) is (A) 10.5 g cm-3 (B) 12.5 g cm3 (C) 5 g cm-2 (D) 15.7 g cm-3

Tardigrade Admin · Accepted Answer

Since the lattice is ccp the number of silver atoms per unit cell = Z = 4 Molar mass of silver =107.9 g mol-1=107.9× 10-3 kg mol-1 Edge length of unit cell =a=408.6 pm = 408.6 × 10-12 m Density, d=(Z. M/a3⋅ NA) =(4×(107.9×10-3 kg mol-1)/(408.6×10-12 m)3(6.022×1023 mol-1 )) =10.5×103 kg m-3=10.5 g cm-3

Q. Silver forms $cc p$ lattice and $X$ -ray studies of its crystals show that the edge length of its unit cell is $408.6 p m$ The density of silver (Atomic mass $= 107.9 u)$ is

$10.5 g c m^{- 3}$

$12.5 g c m^{3}$

$5 g c m^{- 2}$

$15.7 g c m^{- 3}$

Q. Silver forms ccp lattice and X-ray studies of its crystals show that the edge length of its unit cell is 408.6pm The density of silver (Atomic mass =107.9u) is

10.5gcm−3

12.5gcm3

5gcm−2

15.7gcm−3

Q. Silver forms $cc p$ lattice and $X$ -ray studies of its crystals show that the edge length of its unit cell is $408.6 p m$ The density of silver (Atomic mass $= 107.9 u)$ is

$10.5 g c m^{- 3}$

$12.5 g c m^{3}$

$5 g c m^{- 2}$

$15.7 g c m^{- 3}$