Silver crystallizes in face-centered cubic structure. The 2nd order diffraction angle of a beam of X-ray (λ=1 mathringA ) of crystal is 30. Therefore, the distance between the plane would be

Question

Silver crystallizes in face-centered cubic structure. The 2nd order diffraction angle of a beam of X-ray (λ=1 mathringA ) of crystal is 30. Therefore, the distance between the plane would be (A) 1.414 mathringA (B) 2 mathringA (C) 2.45 mathringA (D) 1.714 mathringA

Tardigrade Admin · Accepted Answer

Using Bragg equation, n λ=2d sin θ d=(n λ/2 sin θ)=((2) (1)/(2) sin 30°) d=(1/1/2)=2 mathringA

Q. Silver crystallizes in face-centered cubic structure. The $2 n d$ order diffraction angle of a beam of X-ray $(λ = 1 \overset{˚}{A})$ of crystal is $30$ . Therefore, the distance between the plane would be

$1.414 \overset{˚}{A}$

$2 \overset{˚}{A}$

$2.45 \overset{˚}{A}$

$1.714 \overset{˚}{A}$

Using Bragg equation, $nλ = 2 d s in θ$
$d = \frac{nλ}{2 s in θ} = \frac{( 2 ) ( 1 )}{( 2 ) s in 3 0 ^{\circ}}$
$d = \frac{1}{1/2} = 2 \overset{˚}{A}$

Q. Silver crystallizes in face-centered cubic structure. The 2nd order diffraction angle of a beam of X-ray (λ=1A˚) of crystal is 30. Therefore, the distance between the plane would be

1.414A˚

2A˚

2.45A˚

1.714A˚